ezpz
This commit is contained in:
BasGremmen
parent
933af159cd
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159
Book_1.ipynb
159
Book_1.ipynb
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@ -18,7 +18,7 @@
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},
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{
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"cell_type": "code",
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"execution_count": 5,
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"execution_count": 3,
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"id": "1e6ac084-5bf9-43f7-a7a6-8c8e20066159",
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"metadata": {},
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"outputs": [],
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@ -318,6 +318,161 @@
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" total+= asterisk['numbers'][0] * asterisk['numbers'][1]\n",
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"total"
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]
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},
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{
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"cell_type": "markdown",
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"id": "db726345-15cd-4692-9d98-a8d3a28adfeb",
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"metadata": {},
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"source": [
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"## Puzzel 4"
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]
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},
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{
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"cell_type": "markdown",
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"id": "42c8bc93-34b9-4722-850a-bc4c15212fd8",
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"metadata": {},
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"source": [
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"### Deel 1"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 2,
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"id": "2cbabb08-e696-4466-8963-844ec7d8fc15",
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"metadata": {},
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"outputs": [],
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"source": [
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"data = open('data/puzzle_4.txt', 'r').readlines()"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 19,
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"id": "813183a3-31df-4cb2-a4f4-cbb0db517cb2",
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"metadata": {},
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"outputs": [
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{
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"name": "stdout",
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"output_type": "stream",
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"text": [
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"21568\n"
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]
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}
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],
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"source": [
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"# initiating output variable\n",
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"total = 0\n",
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"for line in data:\n",
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" # Cleaning identifier as it is not necessary\n",
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" line_number_part = line.split(':')[1]\n",
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"\n",
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" # Removing the \\n \n",
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" line_number_part = re.sub('\\n', '',line_number_part)\n",
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"\n",
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" # Creating a set with winning numbers and with owned numbers\n",
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" winning_numbers, owned_numbers = line_number_part.split('|')\n",
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"\n",
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" # Getting the seperate numbers\n",
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" winning_numbers = re.findall('(\\d+)', winning_numbers)\n",
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" owned_numbers = re.findall('(\\d+)', owned_numbers)\n",
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"\n",
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" # Converting to a set to prepare for intersect\n",
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" winning_set = set(winning_numbers)\n",
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" owned_set = set(owned_numbers)\n",
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"\n",
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" # Only numbers that are both owned and winning will be left\n",
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" winning_numbers_owned = winning_set.intersection(owned_set)\n",
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"\n",
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" # Get the number of matches\n",
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" matched_number_count = len(winning_numbers_owned)\n",
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"\n",
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" # If there are no matches, we add nothing to total, so we check for zero matches\n",
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" if matched_number_count > 0:\n",
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" # We then add to the total 2 to the power of the total number of matches minus one, as we start at 1 instead of 2 and 2^0 is 1 \n",
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" total += 2**(matched_number_count-1)\n",
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"print(total)"
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]
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},
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{
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"cell_type": "markdown",
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"id": "9d818873-9540-4de8-881a-620c02ddefca",
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"metadata": {},
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"source": [
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"### Deel 2"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 23,
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"id": "64ac3677-aa84-4059-981a-857632b827c8",
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"metadata": {},
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"outputs": [
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{
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"name": "stdout",
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"output_type": "stream",
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"text": [
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"11827296\n"
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]
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}
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],
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"source": [
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"# initiating output variable\n",
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"total = 0\n",
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"winning_numbers_on_card = []\n",
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"card_numbers = []\n",
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"copies_of_card = []\n",
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"for line in data:\n",
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" # Cleaning identifier\n",
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" card_identifier_part, line_number_part = line.split(':')\n",
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" identifier = int(re.search('\\d+', card_identifier_part).group())\n",
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"\n",
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" # adding to the list\n",
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" card_numbers.append(identifier)\n",
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"\n",
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" # Also adding a 1 to the owned cards list\n",
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" copies_of_card.append(1)\n",
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"\n",
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" # Removing the \\n \n",
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" line_number_part = re.sub('\\n', '',line_number_part)\n",
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"\n",
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" # Creating a set with winning numbers and with owned numbers\n",
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" winning_numbers, owned_numbers = line_number_part.split('|')\n",
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"\n",
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" # Getting the seperate numbers\n",
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" winning_numbers = re.findall('(\\d+)', winning_numbers)\n",
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" owned_numbers = re.findall('(\\d+)', owned_numbers)\n",
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"\n",
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" # Converting to a set to prepare for intersect\n",
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" winning_set = set(winning_numbers)\n",
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" owned_set = set(owned_numbers)\n",
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"\n",
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" # Only numbers that are both owned and winning will be left\n",
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" winning_numbers_owned = winning_set.intersection(owned_set)\n",
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"\n",
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" # Get the number of matches\n",
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" matched_number_count = len(winning_numbers_owned)\n",
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"\n",
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" # Add to card info list\n",
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" winning_numbers_on_card.append(matched_number_count)\n",
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"\n",
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"\n",
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"# Just simulating the rounds, if a card has winining numbers, loop over a range and add that loop variable to the card number\n",
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"# if the card number exists, we simply add the number of copies of the current card to that card\n",
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"# etc. \n",
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"for i, card_id in enumerate(card_numbers):\n",
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" winning_numbers = winning_numbers_on_card[i]\n",
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" for number in range(1, winning_numbers+1):\n",
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" if (card_id+number) in card_numbers:\n",
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" id_to_add_to = card_numbers.index(card_id+number)\n",
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" copies_of_card[id_to_add_to] += copies_of_card[i]\n",
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"\n",
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"# just sum the total cards at the end\n",
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"print(sum(copies_of_card))\n",
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" \n",
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" \n",
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" \n",
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" "
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]
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}
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],
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"metadata": {
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@ -336,7 +491,7 @@
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"name": "python",
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"nbconvert_exporter": "python",
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"pygments_lexer": "ipython3",
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"version": "3.8.8"
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"version": "3.10.13"
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}
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},
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"nbformat": 4,
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112
pretty_read.md
112
pretty_read.md
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@ -193,3 +193,115 @@ total
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81296995
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## Puzzel 4
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### Deel 1
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```python
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data = open('data/puzzle_4.txt', 'r').readlines()
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```
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```python
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# initiating output variable
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total = 0
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for line in data:
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# Cleaning identifier as it is not necessary
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line_number_part = line.split(':')[1]
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# Removing the \n
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line_number_part = re.sub('\n', '',line_number_part)
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# Creating a set with winning numbers and with owned numbers
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winning_numbers, owned_numbers = line_number_part.split('|')
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# Getting the seperate numbers
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winning_numbers = re.findall('(\d+)', winning_numbers)
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owned_numbers = re.findall('(\d+)', owned_numbers)
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# Converting to a set to prepare for intersect
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winning_set = set(winning_numbers)
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owned_set = set(owned_numbers)
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# Only numbers that are both owned and winning will be left
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winning_numbers_owned = winning_set.intersection(owned_set)
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# Get the number of matches
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matched_number_count = len(winning_numbers_owned)
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# If there are no matches, we add nothing to total, so we check for zero matches
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if matched_number_count > 0:
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# We then add to the total 2 to the power of the total number of matches minus one, as we start at 1 instead of 2 and 2^0 is 1
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total += 2**(matched_number_count-1)
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print(total)
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```
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21568
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### Deel 2
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```python
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# initiating output variable
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total = 0
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winning_numbers_on_card = []
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card_numbers = []
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copies_of_card = []
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for line in data:
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# Cleaning identifier
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card_identifier_part, line_number_part = line.split(':')
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identifier = int(re.search('\d+', card_identifier_part).group())
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# adding to the list
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card_numbers.append(identifier)
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# Also adding a 1 to the owned cards list
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copies_of_card.append(1)
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# Removing the \n
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line_number_part = re.sub('\n', '',line_number_part)
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# Creating a set with winning numbers and with owned numbers
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winning_numbers, owned_numbers = line_number_part.split('|')
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# Getting the seperate numbers
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winning_numbers = re.findall('(\d+)', winning_numbers)
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owned_numbers = re.findall('(\d+)', owned_numbers)
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# Converting to a set to prepare for intersect
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winning_set = set(winning_numbers)
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owned_set = set(owned_numbers)
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# Only numbers that are both owned and winning will be left
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winning_numbers_owned = winning_set.intersection(owned_set)
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# Get the number of matches
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matched_number_count = len(winning_numbers_owned)
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# Add to card info list
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winning_numbers_on_card.append(matched_number_count)
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# Just simulating the rounds, if a card has winining numbers, loop over a range and add that loop variable to the card number
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# if the card number exists, we simply add the number of copies of the current card to that card
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# etc.
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for i, card_id in enumerate(card_numbers):
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winning_numbers = winning_numbers_on_card[i]
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for number in range(1, winning_numbers+1):
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if (card_id+number) in card_numbers:
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id_to_add_to = card_numbers.index(card_id+number)
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copies_of_card[id_to_add_to] += copies_of_card[i]
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# just sum the total cards at the end
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print(sum(copies_of_card))
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```
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11827296
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